0=9p^2-2p+96

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Solution for 0=9p^2-2p+96 equation: 



0=9p^2-2p+96

We move all terms to the left:

0-(9p^2-2p+96)=0

We add all the numbers together, and all the variables

-(9p^2-2p+96)=0

We get rid of parentheses

-9p^2+2p-96=0

a = -9; b = 2; c = -96;
Δ = b2-4ac
Δ = 22-4·(-9)·(-96)
Δ = -3452
Delta is less than zero, so there is no solution for the equation

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